AP EAMCET · Maths · Vector Algebra
If \(\mathrm{P}=(\overline{\mathrm{a}} \times \overline{\mathrm{i}})^2+(\overline{\mathrm{a}} \times \overline{\mathrm{j}})^2+(\overline{\mathrm{a}} \times \overline{\mathrm{k}})^2\) and \(\mathrm{Q}=(\overline{\mathrm{a}} \cdot \overline{\mathrm{i}})^2+(\overline{\mathrm{a}} \cdot \overline{\mathrm{j}})^2+(\overline{\mathrm{a}} \cdot \overline{\mathrm{k}})^2\), then
- A \(P=Q\)
- B \(P=2 Q\)
- C \(P=3 Q\)
- D \(P=4 Q\)
Answer & Solution
Correct Answer
(B) \(P=2 Q\)
Step-by-step Solution
Detailed explanation
\(Q = (|\overline{\mathrm{a}}| \cos \theta_x)^2 + (|\overline{\mathrm{a}}| \cos \theta_y)^2 + (|\overline{\mathrm{a}}| \cos \theta_z)^2\) \(Q = |\overline{\mathrm{a}}|^2 (\cos^2 \theta_x + \cos^2 \theta_y + \cos^2 \theta_z)\)…
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