AP EAMCET · Maths · Probability
In a game, a person wins 5 rupees for getting a number greater than 4 and loses 1 rupee otherwise, when a fair die is thrown. A man participated in the game, but decided to quit as and when he gets a number greater than 4. Then the expected value (mean value) of the amount he wins/loses is
- A \(\frac{9}{19}\)
- B \(\frac{8}{19}\)
- C \(\frac{19}{9}\)
- D \(\frac{19}{8}\)
Answer & Solution
Correct Answer
(C) \(\frac{19}{9}\)
Step-by-step Solution
Detailed explanation
In a game die is thrown. A man participated in the game, he decided to throw a die thrice but to quit as and when the amount he win/loses is The probability to win in a throw is \(\frac{2}{6}\) and loss a throw is \(\frac{4}{6}\). Now following cases are possible (i)…
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