AP EAMCET · Maths · Definite Integration
If \(n \geq 2\) is a natural number and \(0 \lt \theta \lt \frac{\pi}{2}\), then \(\int \frac{\left(\cos ^n \theta-\cos \theta\right)^{1 / n}}{\cos ^{n+1} \theta} \sin \theta d \theta=\)
- A \(\frac{n}{n-1}\left(\cos ^{(1-n)} \theta-1\right)^2+c\)
- B \(\frac{n}{(n+1)(1-n)}\left(\cos ^{(1-n)} \theta-1\right)^{1+\frac{1}{n}}+c\)
- C \(\frac{n}{1-n}\left(\cos ^{(n-1)} \theta-1\right)^2+c\)
- D \(\frac{n}{1-n^2}\left(1-\cos ^{(n-1)} \theta\right)^{(n+1) / n}\)
Answer & Solution
Correct Answer
(D) \(\frac{n}{1-n^2}\left(1-\cos ^{(n-1)} \theta\right)^{(n+1) / n}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{I}=\int \frac{\left(\cos ^n \theta-\cos \theta\right)^{\frac{1}{n}}}{\cos ^{n+1} \theta} \sin \theta d \theta\) \(I=\int \frac{\cos \theta\left(1-\cos ^{1-n} \theta\right)^{\frac{1}{n}}}{\cos ^{n+1} \theta} \sin \theta d \theta\)…
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