AP EAMCET · Maths · Application of Derivatives
Equation of tangent to the curve \(y=x+\frac{4}{x^2}\) which is parallel to \(X\)-axis is
- A \(y=8\)
- B \(y=0\)
- C \(y=3\)
- D \(y=2\)
Answer & Solution
Correct Answer
(C) \(y=3\)
Step-by-step Solution
Detailed explanation
\[ y=x+\frac{4}{x^2} \Rightarrow y^{\prime}=1-\frac{8}{x^3} \] As tangent is parallel to \(X\)-axis, \(y^{\prime}=0 \Rightarrow x=2\) At \(x=2, y=3\). \(\therefore\) Equation of tangent is \(y=3\)
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