AP EAMCET · Maths · Complex Number
If \(\omega\) is a complex cube root of unity and \(a, b, c\) are distinct real numbers, then
\[
\frac{a+b \omega+c \omega^2}{c+a \omega+b \omega^2}+\frac{a+b \omega+c \omega^2}{b+c \omega+a \omega^2}=
\]
- A 1
- B -1
- C \(a+b+c\)
- D 0
Answer & Solution
Correct Answer
(B) -1
Step-by-step Solution
Detailed explanation
\( \frac{a+b \omega+c \omega^2}{c+a \omega+b \omega^2} = \frac{a+b \omega+c \omega^2}{\frac{\omega^2(a+b \omega+c \omega^2)}{\omega^2}} = \omega^2 \)…
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