AP EAMCET · Maths · Indefinite Integration
If \(I_n=\int \frac{t^{2 n}}{1+t^2} d t\), then \(I_{n+1}=\)
- A \(\frac{t^{2 n+1}}{2 n+1}+I_{2 n}\)
- B \(\frac{t^{2 n+1}}{2 n+1}+I_n\)
- C \(\frac{t^{2 n+1}}{2 n+1}-I_{2 n}\)
- D \(\frac{t^{2 n+1}}{2 n+1}-I_n\)
Answer & Solution
Correct Answer
(D) \(\frac{t^{2 n+1}}{2 n+1}-I_n\)
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Detailed explanation
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