AP EAMCET · Maths · Continuity and Differentiability
If \(f: \mathbf{R} \rightarrow \mathbf{R}\) is defined by
\[
f(x)=\left\{\begin{array}{cl}
x-1, & \text { for } x \leq 1 \\
2-x^2, & \text { for } 1 < x \leq 3 \\
x-10, & \text { for } 3 < x < 5 \\
2 x, & \text { for } x \geq 5
\end{array}\right.
\]
then the set of points of discontinuity of \(f\) is
- A \(\mathbf{R}-\{1,5\}\)
- B \(\{1,3,5\}\)
- C \(\{1,5\}\)
- D \(\mathbf{R}-\{1,3,5\}\)
Answer & Solution
Correct Answer
(C) \(\{1,5\}\)
Step-by-step Solution
Detailed explanation
Given function \[ f(x)= \begin{cases}x-1, & \text { for } x \leq 1 \\ 2-x^2, & \text { for } 1 < x \leq 3 \\ x-10, & \text { for } 3 < x < 5 \\ 2 x, & \text { for } x \geq 5\end{cases} \] So, \(f(x)\) will be continuous in the intervals \((-\infty, 1),(1,3),(3,5)\) and…
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