AP EAMCET · Maths · Indefinite Integration
If \(f\) is integrable on \([0, a]\), then the function \(h\) defined on \([0, a]\) as \(h(x)=\ldots . . \forall x \in[0, a]\) is integrable on \([0, a]\)
- A \(f(a-x)\)
- B \(f(x-a)\)
- C \(f(x)\)
- D \(f(a)\)
Answer & Solution
Correct Answer
(A) \(f(a-x)\)
Step-by-step Solution
Detailed explanation
Given, \(f\) is integrable an \([0, a]\) \(\begin{aligned} \therefore \quad h(x) & =\int_0^a f(x) d x \\ h(x) & =\int_0^a f(a-x) d x \end{aligned}\) Hence, option (a) is correct.
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