AP EAMCET · Maths · Matrices
If \(\left(\begin{array}{l}\alpha \\ \beta \\ \gamma\end{array}\right)=\left(\begin{array}{ccc}\cos \theta & -\sin \theta & 0 \\ \sin \theta & \cos \theta & 0 \\ 0 & 0 & 1\end{array}\right)\left(\begin{array}{l}x \\ y \\ z\end{array}\right)\), then \(\frac{x^2+y^2+z^2}{\gamma}=\)
- A \(\frac{\alpha^2+\beta^2+\gamma^2}{z}\)
- B \(0\)
- C \(\alpha \beta+\beta \gamma+\gamma \alpha\)
- D \(1+\alpha^2+\beta^2+\gamma^2\)
Answer & Solution
Correct Answer
(A) \(\frac{\alpha^2+\beta^2+\gamma^2}{z}\)
Step-by-step Solution
Detailed explanation
\(\left(\begin{array}{l}\alpha \\ \beta \\ \gamma\end{array}\right)=\left(\begin{array}{ccc}\cos \theta & -\sin \theta & 0 \\ \sin \theta & \cos \theta & 0 \\ 0 & 0 & 1\end{array}\right)\left(\begin{array}{l}x \\ y \\ z\end{array}\right)\)…
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