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AP EAMCET · Maths · Definite Integration

\(\int_{-1}^2|x| d x=\)

  1. A 1
  2. B 2
  3. C \(\frac{5}{2}\)
  4. D \(\frac{3}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{5}{2}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} I & =\int_{-1}^2|x| d x=\int_{-1}^0(-x) d x+\int_0^2(x) d x \\ & =\left[\frac{-x^2}{2}\right]_{-1}^0+\left[\frac{x^2}{2}\right]_0^2=\left(0+\frac{1}{2}\right)+\left(\frac{4}{2}-0\right)=\frac{5}{2} \end{aligned}\)