AP EAMCET · PHYSICS · Oscillations
If the maximum velocity and maximum acceleration of a particle executing simple harmonic motion are respectively \(5 \mathrm{~m} \mathrm{~s}^{-1}\) and \(10 \mathrm{~m} \mathrm{~s}^{-2}\), then the time period of oscillation of the particle is
- A \(\pi \mathrm{S}\)
- B \(2 \pi \mathrm{~s}\)
- C \(2 s\)
- D \(1 s\)
Answer & Solution
Correct Answer
(A) \(\pi \mathrm{S}\)
Step-by-step Solution
Detailed explanation
\( \omega = \frac{a_{max}}{v_{max}} \) \( \omega = \frac{10 \mathrm{~m} \mathrm{~s}^{-2}}{5 \mathrm{~m} \mathrm{~s}^{-1}} = 2 \mathrm{~s}^{-1} \) \( T = \frac{2\pi}{\omega} \) \( T = \frac{2\pi}{2 \mathrm{~s}^{-1}} = \pi \mathrm{s} \)
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