AP EAMCET · Maths · Quadratic Equation
If \(\alpha, \beta\) and \(\gamma\) are the roots of the equation \(x^3+a^2+b x\) \(+c=0\), then the roots of the equation \(x^3+\left(2 b-a^2\right) x^2+\) \(\left(b^2-2 a c\right) x-c^2=0\) are
- A \(\alpha^3, \beta^3, \gamma^3\)
- B \((\alpha+1)^2,(\beta+1)^2,(\gamma+1)^2\)
- C \(\alpha^2, \beta^2, \gamma^2\)
- D \((\alpha-1)^2,(\beta-1)^2,(\gamma-1)^2\)
Answer & Solution
Correct Answer
(C) \(\alpha^2, \beta^2, \gamma^2\)
Step-by-step Solution
Detailed explanation
\(\because \alpha, \beta\) and \(\gamma\) are roots of \(x^3+a^2+b x+c=0\) \(\therefore \alpha+\beta+\gamma=-a \Rightarrow a=-(\alpha+\beta+\gamma)\)…
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