AP EAMCET · Maths · Vector Algebra
\(\vec{a}\) and \(\vec{b}\) are two vectors such that \(\vec{a}\) is not parallel to \(\vec{b}\). If \(\overrightarrow{\mathrm{p}}=(\mathrm{x}+2 \mathrm{y}+3) \overrightarrow{\mathrm{a}}+(5 \mathrm{x}-\mathrm{y}+2) \overrightarrow{\mathrm{b}}\) and \(\overrightarrow{\mathrm{q}}=(2 \mathrm{x}+3 \mathrm{y}+5)\) \(\vec{a}+(x-5 y-2) \vec{b}\) are two vectors such that \(\vec{p}=2 \vec{q}\), then \(\mathrm{x}-2 \mathrm{y}=\)
- A 3
- B 2
- C -2
- D -3
Answer & Solution
Correct Answer
(B) 2
Step-by-step Solution
Detailed explanation
\[ \begin{aligned} & \text { } \bar{p}=2 \bar{q} \\ & \Rightarrow(x+2 y+3) \bar{a}+(5 x-y+2) \bar{b} \\ & (4 x+6 y+10) \vec{a}+(2 x-10 y-9) \vec{b} \end{aligned} \] Comparing both sides we get…
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