AP EAMCET · Maths · Probability
If a cubical die is thrown, then the mean and variance of the random variable \(\mathrm{X}\), giving the number on the face that shows up, are respectively
- A \(\frac{2}{7}, \frac{12}{35}\)
- B \(\frac{7}{2}, \frac{12}{35}\)
- C \(\frac{1}{7}, \frac{1}{12}\)
- D \(\frac{7}{2}, \frac{35}{12}\)
Answer & Solution
Correct Answer
(D) \(\frac{7}{2}, \frac{35}{12}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { } X=\{1,2,3,4,5,6\} \text { and } P(1)=P(2) \ldots P(6)=\frac{1}{6} \\ & \text { Mean }=\sum x_i \cdot P=\frac{1+2+3+4+5+6}{6}=\frac{21}{6}=\frac{7}{2} \\ & \text { Variance }=\sum x_i^2 \cdot P-(\text { Mean })^2 \\ &…
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