AP EAMCET · Maths · Vector Algebra
If \(A, B, C\) and \(D\) are four points in the plane such that \(|\mathbf{A B}|^2+|\mathbf{C D}|^2=|\mathbf{B C}|^2+|\mathbf{D A}|^2=100\), then \(\mathbf{A C} \cdot \mathbf{B D}=\)
- A 10
- B 0
- C \(\frac{1}{10}\)
- D 1
Answer & Solution
Correct Answer
(B) 0
Step-by-step Solution
Detailed explanation
Let \(A, B, C\) and \(D\) are vertices of a quadrilateral So, \[ |\mathbf{A C}|^2+|\mathbf{B D}|^2=|\mathbf{A B}|^2+|\mathbf{C D}|^2+2 \mathbf{B C} \cdot \mathbf{A D} \] and…
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