AP EAMCET · Maths · Circle
If \((a, b)\) and \((c, d)\) are the internal and external centres of similitudes of the circles \(x^2+y^2+4 x-5=0\) and \(x^2+y^2\) \(-6 y+8=0\) respectively, then \((a+d)(b+c)=\)
- A \(4\)
- B \(9\)
- C \(13\)
- D \(22\)
Answer & Solution
Correct Answer
(C) \(13\)
Step-by-step Solution
Detailed explanation
Given equation of two circle \(x^2+y^2+4 x-5=0 \text { and } x^2+y^2-6 y+8=0\) \(\Rightarrow(x+2)^2+y^2=3^2 \text { and, } x^2+(y-3)^2=1\) So, \(\mathrm{C}_1=(-2,0), r_1=3 ; \mathrm{C}_2=(0,3), r_2=1\)…
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