AP EAMCET · PHYSICS · Gravitation
A body is projected up with a velocity equal to \(\frac{3}{4}\) th of the escape velocity from the surface of the earth. The height it reaches is (Radius of the earth \(=R\) )
- A \(\frac{10 R}{9}\)
- B \(\frac{9 R}{7}\)
- C \(\frac{9 R}{8}\)
- D \(\frac{10 R}{3}\)
Answer & Solution
Correct Answer
(B) \(\frac{9 R}{7}\)
Step-by-step Solution
Detailed explanation
Velocity of projection \(v=\frac{3}{4} v_e\) where, \(v_e=\) escape velocity \(=\sqrt{2 g R}\) Maximum height attained by the body…
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