AP EAMCET · Maths · Three Dimensional Geometry
The direction cosines of the line of intersection of the planes \(x+2 y+z-4=0\) and \(2 x-y+z-3=0\) are
- A \(\left(\frac{3}{\sqrt{26}}, \frac{1}{\sqrt{26}}, \frac{-4}{\sqrt{26}}\right)\)
- B \(\left(\frac{3}{\sqrt{14}}, \frac{2}{\sqrt{14}}, \frac{-1}{\sqrt{14}}\right)\)
- C \(\left(\frac{3}{\sqrt{35}}, \frac{1}{\sqrt{35}}, \frac{-5}{\sqrt{35}}\right)\)
- D \(\left(\frac{3}{\sqrt{22}}, \frac{-2}{\sqrt{22}}, \frac{3}{\sqrt{22}}\right)\)
Answer & Solution
Correct Answer
(C) \(\left(\frac{3}{\sqrt{35}}, \frac{1}{\sqrt{35}}, \frac{-5}{\sqrt{35}}\right)\)
Step-by-step Solution
Detailed explanation
\(2 x-y+z-3=0\) \(\qquad ...\mathrm{(i)}\) \(x+2 y+z-4=0\) \(\qquad ...\mathrm{(ii)}\) Solving (i) and (ii) \(x=-1, y=0, z=5\) Line of intersection is parallel to \(\vec{r}_1 \times \vec{r}_2\)…
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