AP EAMCET · Maths · Circle
If \(\sin ^{-1}(a)\) is the acute angle between the curves \(x^2+y^2=4 x\) and \(x^2+y^2=8\) at the point \((2,2)\), then \(a\) is equal to
- A \(1\)
- B \(\frac{1}{\sqrt{2}}\)
- C \(0\)
- D \(\frac{-1}{\sqrt{2}}\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{\sqrt{2}}\)
Step-by-step Solution
Detailed explanation
Given, curves are : \(x^2+y^2=4 x\) ...(i) and\(x^2+y^2=8\) ...(ii) \(\because \frac{d y}{d x}\) is the slope of tangent drawn to curve Slope of the tangent drawn to curve (i) is \(m_1=\frac{d y}{d x} \quad\) [from curve (i)] On differentiating Eq. (i) w.r.t. \(x\)…
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