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AP EAMCET · Maths · Functions

If \(f: A \rightarrow B\) is an onto function such that \(f(x)=\sqrt{|x|-x}+\frac{1}{\sqrt{|x|-x}}\), then \(A\) and \(B\) are respectively.

  1. A \((-\infty, \infty),(0, \infty)\)
  2. B \((-\infty, 0),[2, \infty)\)
  3. C \((0, \infty),(2, \infty)\)
  4. D \((-\infty, 0],(0, \infty)\)
Verified Solution

Answer & Solution

Correct Answer

(B) \((-\infty, 0),[2, \infty)\)

Step-by-step Solution

Detailed explanation

We have, \(f(x)=\sqrt{|x|-x}+\frac{1}{\sqrt{|x|-x}}\) We know that, \(f(x)\) will be defined when \(\begin{array}{lrl} & & |x|-x > 0 \\ \Rightarrow & & |x| > x \\ \therefore & x \in(-\infty, 0) \end{array}\) Now,…