AP EAMCET · Maths · Functions
If \(f: A \rightarrow B\) is an onto function such that \(f(x)=\sqrt{|x|-x}+\frac{1}{\sqrt{|x|-x}}\), then \(A\) and \(B\) are respectively.
- A \((-\infty, \infty),(0, \infty)\)
- B \((-\infty, 0),[2, \infty)\)
- C \((0, \infty),(2, \infty)\)
- D \((-\infty, 0],(0, \infty)\)
Answer & Solution
Correct Answer
(B) \((-\infty, 0),[2, \infty)\)
Step-by-step Solution
Detailed explanation
We have, \(f(x)=\sqrt{|x|-x}+\frac{1}{\sqrt{|x|-x}}\) We know that, \(f(x)\) will be defined when \(\begin{array}{lrl} & & |x|-x > 0 \\ \Rightarrow & & |x| > x \\ \therefore & x \in(-\infty, 0) \end{array}\) Now,…
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