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AP EAMCET · Maths · Complex Number

If a>0 and z=x+iy, then logcos2θ|z-a|>logcos2θ|z-ai|,(θR) implies

  1. A x>y
  2. B x<y
  3. C x+y=cosθ
  4. D x+y<0
Verified Solution

Answer & Solution

Correct Answer

(A) x>y

Step-by-step Solution

Detailed explanation

logcos2θ|z−a|>logcos2θ|z−ai| cos2θ≠0, 1, since it is base of the logarithm So, cos2θ∈0,1 ⇒|z−a|<|z−ai| ⇒|x+yi−a|<|x+yi−ai| ⇒|(x−a)+yi|<|x+(y−a)i|…