AP EAMCET · Maths · Straight Lines
In a triangle \(\mathrm{ABC},(\mathrm{b}+\mathrm{c}) \sin \frac{A}{2}=\)
- A \(a \cos A\)
- B \(a \cos \left(\frac{B-C}{2}\right)\)
- C \(a \sin \left(\frac{B+C}{2}\right)\)
- D \(a \sin \left(\frac{B-C}{2}\right)\)
Answer & Solution
Correct Answer
(B) \(a \cos \left(\frac{B-C}{2}\right)\)
Step-by-step Solution
Detailed explanation
In \(\varnothing \mathrm{ABC}(\mathrm{b}+\mathrm{c}) \operatorname{Sin}\left(\frac{\mathrm{A}}{2}\right)=\) ? By \(\operatorname{Sin}\) rule \(\frac{a}{\operatorname{Sin} A}=\frac{b}{\operatorname{Sin} A}=\frac{c}{\operatorname{Sin} C}=k\)…
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