AP EAMCET · Maths · Three Dimensional Geometry
A line L intersects the lines \(3 x-2 y-1=0\) and \(x+2 y+\) \(1=0\) at the points A and B . If the point \((1,2)\) bisects the line segment AB and \(\frac{x}{a}+\frac{y}{b}=1\) is the equation of the line L. then \(a+2 b+1=\)
- A \(-1\)
- B \(0\)
- C \(1\)
- D \(2\)
Answer & Solution
Correct Answer
(D) \(2\)
Step-by-step Solution
Detailed explanation
Let point of intersection \(A\left(x_1, y_1\right)\) and \(B\left(x_2, y_2\right)\) \(\therefore \frac{x_1+x_2}{2}=1 \Rightarrow x_2=2-x_1 \Rightarrow \frac{y_1+y_2}{2}=2 \Rightarrow y_2=4-y_1\) \(\because\) A lies on \(3 x-2 y-1=0\) \(\therefore 3 x_1-2 y_1-1=0\) ....(i) and…
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