AP EAMCET · Maths · Application of Derivatives
A value of \(c\) according to the Lagrange's mean value theorem for \(f(x)=(x-1)(x-2)(x-3)\) in \([0,4]\) is
- A \(2+\frac{2}{\sqrt{3}}\)
- B \(2-\sqrt{\frac{16}{3}}\)
- C \(1+\sqrt{\frac{5}{4}}\)
- D \(2+\sqrt{\frac{8}{3}}\)
Answer & Solution
Correct Answer
(A) \(2+\frac{2}{\sqrt{3}}\)
Step-by-step Solution
Detailed explanation
\(f(x)=(x-1)(x-2)(x-3)\) in \([0,4]\) By lagrange's mean value theorem…
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