AP EAMCET · Maths · Circle
If \((6,-k)\) and \((-3,2)\) are conjugate points with respect to circle \(x^2+y^2+6 x+4 y+12=0\), then \(k\) equals
- A \(\frac{-7}{4}\)
- B \(\frac{7}{4}\)
- C \(\frac{4}{7}\)
- D \(\frac{-4}{7}\)
Answer & Solution
Correct Answer
(B) \(\frac{7}{4}\)
Step-by-step Solution
Detailed explanation
Points \((6,-k)\) and \((-3,2)\) are conjugate points to the circle \(x^2+y^2+6 x+4 y+12=0\) \(\therefore\) We know that if \(\left(x_1, y_1\right)\) and \(\left(x_2, y_2\right)\) are conjugate points of circle \[ x^2+y^2+2 g x+2 f y+c=0 \] Then,…
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