AP EAMCET · Maths · Complex Number
If \(\alpha=\cos \frac{\pi}{3}+i \sin \frac{\pi}{3}\) then the value of the determinant \(\left|\begin{array}{ccc}1 & \alpha & \alpha^2 \\ \alpha^2 & 1 & \alpha \\ \alpha & \alpha^2 & 1\end{array}\right|\) is
- A 0
- B 1
- C -4
- D 4
Answer & Solution
Correct Answer
(D) 4
Step-by-step Solution
Detailed explanation
\(\alpha^3 = \left(\cos \frac{\pi}{3}+i \sin \frac{\pi}{3}\right)^3 = \cos \pi + i \sin \pi = -1\) \(\alpha^6 = (\alpha^3)^2 = (-1)^2 = 1\)…
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