AP EAMCET · Maths · Probability
A discrete random variable \(X\) has the distribution \(B(15, p)\). Given that \(\operatorname{Var}(X)=3.15\). Then, the two possible values of \(p\) are
- A 0,1
- B \(0.1,0.9\)
- C \(0.4,0.6\)
- D \(0.3,0.7\)
Answer & Solution
Correct Answer
(D) \(0.3,0.7\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { Here, } n=15, q=1-p \\ & \operatorname{Var}(X)=315 ; n p q=315 \\ & \quad 15 \times p(1-p)=315 \\ & \Rightarrow \quad p-p^2=0.21 \Rightarrow p^2-p+0.21=0 \\ & \Rightarrow \quad p^2-0.7 p-0.3 p+0.21=0 \\ & \Rightarrow \quad p(p-0.7)-0.3(p-0.7)=0 \\ &…
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