AP EAMCET · Chemistry · Solutions
Benzene and toluene form an ideal solution over the entire range of composition. The vapour pressure of pure benzene and toluene at \(T(\mathrm{~K})\) are \(50 \mathrm{~mm} \mathrm{Hg}\) and \(40 \mathrm{~mm} \mathrm{Hg}\) respectively. What is the mole fraction of toluene in vapour phase when \(117 \mathrm{~g}\) of benzene is mixed with \(46 \mathrm{~g}\) of toluene? (molar mass of benzene and toluene are 78 and \(92 \mathrm{~g} \mathrm{~mol}^{-1}\) respectively)
- A 0.78
- B 0.21
- C 0.64
- D 0.35
Answer & Solution
Correct Answer
(B) 0.21
Step-by-step Solution
Detailed explanation
\(p^{\circ}\) benzene \(p_{(b)}^{\circ}=50 \mathrm{~mm} \mathrm{Hg}\) \(p^{\circ}\) toluene \(p_{(t)}^{\circ}=40 \mathrm{~mm} \mathrm{Hg}\) Mass of benzene \(=117 \mathrm{~g}\) Mass of toluene \(=46 \mathrm{~g}\) Molar mass of benzene \(=78 \mathrm{~g} \mathrm{~mol}^{-1}\) Molar…
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