AP EAMCET · Maths · Trigonometric Equations
If \(\cos \theta-4 \sin \theta=1\), then \(\sin \theta+4 \cos \theta\) is equal to
- A \(\pm 1\)
- B 0
- C \(\pm 2\)
- D \(\pm 4\)
Answer & Solution
Correct Answer
(D) \(\pm 4\)
Step-by-step Solution
Detailed explanation
Given that \(\cos \theta-4 \sin \theta=1 \ldots\) (i) On squaring both sides of equation (i) \(\cos ^2 \theta+16 \sin ^2 \theta-8 \sin \theta \cos \theta =1 \) \(\Rightarrow 15 \sin ^2 \theta-8 \sin \theta \cos \theta =0 \)…
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