AP EAMCET · Maths · Circle
\(A\) is the centre of the circle \(x^2+y^2-2 x-4 y-20=0\). If the tangents drawn at the points \(B(1,7)\) and \(D(4,-2)\) on the circle meet at the point \(C\), then area of the quadrilateral \(A B C D\) (in square units) is
- A 75
- B 64
- C 56
- D 45
Answer & Solution
Correct Answer
(A) 75
Step-by-step Solution
Detailed explanation
Equation of the given circle is Now, equation of tangent at the point \(B(1,7)\) on the circle is \[ x+7 y-(x+1)-2(y+7)-20=0 \Rightarrow 5 y=35 \] Similarly, equation of tangent at the point \(D(4,-2)\) on the circle is \[ 4 x-2 y-(x+4)-2(y-2)-20=0 \] Now, point of intersection…
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