AP EAMCET · Chemistry · Solutions
When \(10^{-3} \mathrm{M}\) solution of glucose in water, freezes at \(-0.0186^{\circ} \mathrm{C}\), then at what temperature \(10^{-3} \mathrm{M}\) solution of \(\mathrm{NaCl}\) will freeze?
- A \(0{ }^{\circ} \mathrm{C}\)
- B \(0.186^{\circ} \mathrm{C}\)
- C \(-0.186^{\circ} \mathrm{C}\)
- D \(-0.0372^{\circ} \mathrm{C}\)
Answer & Solution
Correct Answer
(D) \(-0.0372^{\circ} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \Delta \mathrm{T}_{\mathrm{f}}=0.0^{\circ} \mathrm{C}-\left(-0.0186^{\circ} \mathrm{C}\right)=0.086^{\circ} \mathrm{C} \\ & \text { (glucose) }\end{aligned}\) \(\Delta \mathrm{T}_{\mathrm{f}}=\mathrm{i} \times \mathrm{m} \times \mathrm{k}_{\mathrm{f}}\) Both…
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