AP EAMCET · Maths · Probability
A box contains 4 defective and 6 good machines. Two machines are selected at random without replacement. Find the probability that both the machines are good.
- A \(\frac{1}{2}\)
- B \(\frac{1}{3}\)
- C \(\frac{1}{4}\)
- D \(\frac{1}{5}\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{3}\)
Step-by-step Solution
Detailed explanation
Box contains 4 defective and 6 good machines. \(\therefore\) Total number of machines \(=10\) Probability that first machine selected is good \(=\frac{\text { Number of good } m / c}{\text { Total number of } m / c}=\frac{6}{10}\) Probability that second machine is good…
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