AP EAMCET · Maths · Binomial Theorem
If \(3 \times{ }^5 \mathrm{C}_0+8 \times{ }^5 \mathrm{C}_1+13 \times{ }^5 \mathrm{C}_2+18 \times{ }^5 \mathrm{C}_3+23 \times{ }^5 \mathrm{C}_4+\) \(28 \times{ }^5 \mathrm{C}_5=\mathrm{k} \times 2^4\), then \(\mathrm{k}=\)
- A 33
- B 37
- C 31
- D 30
Answer & Solution
Correct Answer
(C) 31
Step-by-step Solution
Detailed explanation
\(\begin{aligned} 3 \times{ }^5 C_0+8 \times{ }^5 C_1 & +13 \times{ }^5 C_2+18 \times{ }^5 C_3 \\ & +23 \times{ }^5 C_4+\ldots .+28 \times{ }^5 C_5=k \times 2^4\end{aligned}\)…
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