AP EAMCET · Maths · Trigonometric Equations
If \(\sin \theta+2 \cos \theta=1\) and \(\theta\) belongs to \(4^{\text {th }}\) quadrant (not lying on the coordinate axes) then \(7 \cos \theta+6 \sin \theta=\)
- A \(\frac{4}{17}\)
- B \(2\)
- C \(\frac{7}{17}\)
- D \(\frac{4}{5}\)
Answer & Solution
Correct Answer
(B) \(2\)
Step-by-step Solution
Detailed explanation
\( \sin \theta = 1 - 2 \cos \theta \) \( (1 - 2 \cos \theta)^2 + \cos^2 \theta = 1 \) \( 1 - 4 \cos \theta + 4 \cos^2 \theta + \cos^2 \theta = 1 \) \( 5 \cos^2 \theta - 4 \cos \theta = 0 \) \( \cos \theta (5 \cos \theta - 4) = 0 \) \( \cos \theta = \frac{4}{5} \) (since…
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