AP EAMCET · Maths · Probability
2 aeroplanes I and II bomb a target in succession. The probabilities of I and II scoring a hit correctly is 0.3 and 0.2 respectively. The second plane will bomb only if first misses the target. The probability that the target is hit by the 2 nd plane is
- A \(0.06\)
- B \(0.14\)
- C \(0.32\)
- D \(0.7\)
Answer & Solution
Correct Answer
(C) \(0.32\)
Step-by-step Solution
Detailed explanation
Let \(A\) be the event that aeroplane-I hit the target correctly and \(B\) be the event that aeroplane-II hit the target correctly. \(\begin{array}{ll}\Rightarrow & P(A)=0.3 \text { and } P(B)=0.2 \\ \therefore & P\left(A^{\prime}\right)=1-P(A)=1-0.3=0.7\end{array}\) where…
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