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AP EAMCET · Maths · Indefinite Integration

If \(\int \frac{1}{\left((x+4)^3(x+1)^5\right)^{1 / 4}} d x=A \cdot\left(\frac{x+4}{x+1}\right)^n+c\), then

  1. A n. \(A=3\)
  2. B \(\mathrm{n}+\frac{1}{\mathrm{~A}}=-\frac{1}{2}\)
  3. C \(A+n=1\)
  4. D \(\mathrm{A}=\mathrm{n}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\mathrm{n}+\frac{1}{\mathrm{~A}}=-\frac{1}{2}\)

Step-by-step Solution

Detailed explanation

Let \(u = \frac{x+4}{x+1}\). \(du = \frac{(x+1)-(x+4)}{(x+1)^2} dx = \frac{-3}{(x+1)^2} dx \implies dx = -\frac{1}{3}(x+1)^2 du\). From \(u = \frac{x+4}{x+1}\), \(u(x+1) = x+4 \implies (u-1)(x+1) = 3 \implies x+1 = \frac{3}{u-1}\). So,…