AP EAMCET · Maths · Indefinite Integration
If \(\int \frac{1}{\left((x+4)^3(x+1)^5\right)^{1 / 4}} d x=A \cdot\left(\frac{x+4}{x+1}\right)^n+c\), then
- A n. \(A=3\)
- B \(\mathrm{n}+\frac{1}{\mathrm{~A}}=-\frac{1}{2}\)
- C \(A+n=1\)
- D \(\mathrm{A}=\mathrm{n}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{n}+\frac{1}{\mathrm{~A}}=-\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
Let \(u = \frac{x+4}{x+1}\). \(du = \frac{(x+1)-(x+4)}{(x+1)^2} dx = \frac{-3}{(x+1)^2} dx \implies dx = -\frac{1}{3}(x+1)^2 du\). From \(u = \frac{x+4}{x+1}\), \(u(x+1) = x+4 \implies (u-1)(x+1) = 3 \implies x+1 = \frac{3}{u-1}\). So,…
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