AP EAMCET · Maths · Vector Algebra
If \(P\) is a point lying on the line passing through the point \(A(\hat{\mathbf{i}}-\hat{\mathbf{j}}+3 \hat{\mathbf{k}})\) and parallel to the vector \(2 \hat{\mathbf{i}}+\hat{\mathbf{j}}-2 \hat{\mathbf{k}}\) such that \(|\mathbf{A P}|=18\), then a position vector of \(P\) is
- A \(-13 \hat{\mathbf{i}}-5 \hat{\mathbf{j}}+9 \hat{\mathbf{k}}\)
- B \(11 \hat{\mathbf{i}}+7 \mathbf{j}-15 \hat{\mathbf{k}}\)
- C \(13 \hat{\mathbf{i}}-5 \hat{\mathbf{j}}+9 \hat{\mathbf{k}}\)
- D \(13 \hat{\mathbf{i}}+5 \hat{\mathbf{j}}-9 \hat{\mathbf{k}}\)
Answer & Solution
Correct Answer
(D) \(13 \hat{\mathbf{i}}+5 \hat{\mathbf{j}}-9 \hat{\mathbf{k}}\)
Step-by-step Solution
Detailed explanation
According to the given information, the diagram is shown as below. Given, \(\begin{aligned} \mathbf{A P} & =18 \\ \mathbf{O A} & =\hat{\mathbf{i}}-\hat{\mathbf{j}}+3 \hat{\mathbf{k}} \end{aligned}\) Now,…
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