AP EAMCET · Maths · Circle
If the angle between a pair of tangents drawn from a point \(P\) to the circle \(x^2+y^2+4 x-6 y+9 \sin ^2 \alpha+13 \cos ^2 \alpha=0\) is \(2 \alpha\), then the equation of the locus of \(P\) is
- A \(x^2+y^2+4 x-6 y+4=0\)
- B \(x^2+y^2+4 x-6 y-9=0\)
- C \(x^2+y^2-4 x+6 y-4=0\)
- D \(x^2+y^2+4 x-6 y+9=0\)
Answer & Solution
Correct Answer
(D) \(x^2+y^2+4 x-6 y+9=0\)
Step-by-step Solution
Detailed explanation
According to given information, on drawing the figure.…
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