AP EAMCET · Maths · Hyperbola
If the line \(5 x-2 y-6=0\) is a tangent to the hyperbola \(5 x^2-k y^2=12\). then the equation of the normal to this hyperbola at the point \((\sqrt{6}, p)(p \lt 0)\) is
- A \(\sqrt{6} x+2 y=0\)
- B \(2 \sqrt{6} x+3 y=3\)
- C \(\sqrt{6} x-5 y=21\)
- D \(3 \sqrt{6} x-y=21\)
Answer & Solution
Correct Answer
(C) \(\sqrt{6} x-5 y=21\)
Step-by-step Solution
Detailed explanation
Given equation of hyperbola \(5 x^2-k y^2=12\) \(\Rightarrow \frac{x^2}{\frac{12}{5}}-\frac{y^2}{\frac{12}{k}}=1\) So equation of tangent at \(\left(x_1, y_1\right)\) is…
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