AP EAMCET · Maths · Indefinite Integration
If \(\int \frac{1+\cos (4 x)}{\cot (x)-\tan (x)} d x=A \cos (4 x)+B\), then \(A\) is equal to
- A \(\frac{-1}{2}\)
- B \(\frac{-1}{4}\)
- C \(\frac{-1}{3}\)
- D \(\frac{-1}{8}\)
Answer & Solution
Correct Answer
(D) \(\frac{-1}{8}\)
Step-by-step Solution
Detailed explanation
\(\int \frac{1+\cos (4 x)}{\cos x-\tan x} d x=A \cos (4 x)+B\), then \(A=\) ? Let…
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