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AP EAMCET · Maths · Trigonometric Equations

In a triangle ABC,tanA2tanB2tanC22

  1. A 127
  2. B 118
  3. C 19
  4. D 13
Verified Solution

Answer & Solution

Correct Answer

(A) 127

Step-by-step Solution

Detailed explanation

We know that for ∆ABC tanA2tanB2+tanB2tanC2+tanC2tanA2=1   ....i For triangle, tanA2, tanB2, tanC2>0 Now, AM≥GM ⇒tanA2tanB2+tanB2tanC2+tanC2tanA23≥tanA2tanB2×tanB2tanC2×tanC2tanA213…