ExamBro
ExamBro
AP EAMCET · Maths · Complex Number

If \(1, \omega, \omega^2\) are the cube roots of unity then the value of \((x+y)^2+\left(x \omega+y \omega^2\right)^2+\left(x \omega^2+y \omega\right)^2\) is

  1. A \(2 x^2 \cdot 3 y^2\)
  2. B \(4 x y\)
  3. C \(6 x y\)
  4. D \(2 x^2 \cdot 2 y^2\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(6 x y\)

Step-by-step Solution

Detailed explanation

Given that \(1, \mathrm{w}, \mathrm{w}^2\) are the cube roots of unity. \(\therefore 1+\mathrm{w}+\mathrm{w}^2=0\) and \(\mathrm{w}^3=1\). Now, \((x+y)^2\left(x w+y w^2\right)+\left(x w^2+y w\right)^2\)…
From AP EAMCET
Explore more questions on app