AP EAMCET · Maths · Parabola
If a parabola having its axis parallel to \(\mathrm{X}\)-axis passes through the points \((0,-1),(6,1)\) and \((-2,-3)\), then the point at which this parabola cuts the \(\mathrm{X}\)-axis is
- A \(\left(\frac{5}{2}, 0\right)\)
- B \((-1,0)\)
- C \((6,0)\)
- D \(\left(\frac{8}{5}, 0\right)\)
Answer & Solution
Correct Answer
(A) \(\left(\frac{5}{2}, 0\right)\)
Step-by-step Solution
Detailed explanation
\(\because\) Axis of parabola is \(x\)-axis. \(\therefore\) The equation of the parabola will of the form \(x=a y^2+b y+c\) ...(i) \(\because(0,-1),(6,1)\) and \((-2,-3)\) passes through parabola (i), \(0=a-b+c\) ...(ii) \(6=a+b+c\) ...(iii) \(-2=9 a-3 b+c\) ...(iv) Solving…
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