AP EAMCET · Maths · Probability
8 teachers and 4 students are sitting around a circular table at random, then the probability that no two students sit together is:
- A \(\frac{7}{88}\)
- B \(\frac{14}{33}\)
- C \(\frac{8}{33}\)
- D \(\frac{7}{33}\)
Answer & Solution
Correct Answer
(D) \(\frac{7}{33}\)
Step-by-step Solution
Detailed explanation
Total number of arrangements of 8 teachers and 4 students in circular table \(=(8+4-1)!=11\) ! Number of arrangements of 8 teachers and 4 students in circular table such that no two students sit together \(={ }^8 C_4 \cdot 4!(8-1)!={ }^8 C_4 \cdot 4!\cdot 7!\) \(\therefore\)…
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