AP EAMCET · Maths · Circle
For the circle \(x^2+y^2-9=0\), find the equation of the chord having \((1,2)\) as its mid-point.
- A \(x+2 y+5=0\)
- B \(x-3 y-5=0\)
- C \(x-3 y+5=0\)
- D \(x+2 y-5=0\)
Answer & Solution
Correct Answer
(D) \(x+2 y-5=0\)
Step-by-step Solution
Detailed explanation
Equation of chord having mid-point \((1,2)\) w.r.t. circle \(x^2+y^2-9=0\) is (1) \(x+\) (2) \(y-9=1^2+2^2-9\) \[ \Rightarrow \quad x+2 y=5 \]
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