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AP EAMCET · Maths · Permutation Combination

The number of different words that can be formed from the letters of the word "INTERMEDIATE" such that two vowels never come together, is

  1. A \(\frac{6 !}{2 !} \times \frac{7 !}{2 ! 3 !}\)
  2. B \(\frac{5 !}{2 !} \times \frac{6 !}{3 !}\)
  3. C \(6 ! \times \frac{7 !}{2 ! 3 !}\)
  4. D \(\frac{6 !}{2 !} \times \frac{6 !}{2 ! 3 !}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{6 !}{2 !} \times \frac{7 !}{2 ! 3 !}\)

Step-by-step Solution

Detailed explanation

In the given word "INTERMEDIATE" the vowels and consonants are IEEIAE and NTRMDT respectively. Now number of ways to arrange consonants first is \(\frac{6 !}{2 !}\). Now number of ways to arrange six vowels in the seven available and favourable positions are…
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