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AP EAMCET · Maths · Hyperbola

If the angle between the asymptotes of the hyperbola \(x^2-k y^2=3\) is \(\frac{\pi}{3}\) and \(e\) is its eccentricity, then the pole of the line \(x+y-1=0\) with respect to this hyperbola is

  1. A \(\left(k, \frac{\sqrt{3} e}{2}\right)\)
  2. B \(\left(-k, \frac{\sqrt{3} e}{2}\right)\)
  3. C \(\left(-k,-\frac{\sqrt{3} e}{2}\right)\)
  4. D \(\left(k,-\frac{\sqrt{3} e}{2}\right)\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\left(k,-\frac{\sqrt{3} e}{2}\right)\)

Step-by-step Solution

Detailed explanation

Given the equation of hyperbola is \(x^2-k y^2=3\) \(\Rightarrow \frac{x^2}{3}-\frac{y^2}{\frac{3}{k}}=1\) So, angle between the asymptotes is \(\theta=\tan ^{-1}\left(\frac{2 a b}{a^2-b^2}\right)\)…