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AP EAMCET · Maths · Circle

If a circle \(S\) passes through the origin and makes an intercept of length 4 units on the line \(x=2\), then the equation of the curve on which the centre of \(S\) lies is

  1. A \(y^2-4 x=8\)
  2. B \(y^2+4 x=8\)
  3. C \(x^2+4 y=8\)
  4. D \(x^2-4 y=8\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(y^2+4 x=8\)

Step-by-step Solution

Detailed explanation

Let the center of the circle be \( (h,k) \). Since it passes through the origin \( (0,0) \), the square of the radius is \( r^2 = h^2 + k^2 \). The equation of the circle is \( (x-h)^2 + (y-k)^2 = h^2 + k^2 \). For the intercept on the line \( x=2 \):…
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