AP EAMCET · Maths · Straight Lines
\(\mathrm{f}(\mathrm{x})\) is a continuous function on \(\mathbb{R}\) and \(\mathrm{y}=\mathrm{f}(\mathrm{x})\) is a curve. If \((\alpha, \beta)\) is a point such that \(\beta=f(\alpha)\) and \(p \alpha+m \beta+n=0\) \((\mathrm{p} \neq 0, \mathrm{~m} \neq 0)\), then which one of the following is True?
- A When \(\mathrm{p}+\mathrm{mf}^{\prime}(\alpha)=0, \mathrm{px}+\mathrm{my}+\mathrm{n}=0\) intersects the curve \(y=f(x)\)
- B \(\mathrm{px}+\mathrm{my}+\mathrm{n}=0\) is always a tangent to the curve \(y=f(x)\)
- C When \(\mathrm{p}+\mathrm{mf}^{\prime}(\alpha) \neq 0, \mathrm{px}+\mathrm{my}+\mathrm{n}=0\) intersects the curve \(y=f(x)\)
- D \(\mathrm{px}+\mathrm{my}+\mathrm{n}=0\) is never a tangent to the curve \(y=f(x)\)
Answer & Solution
Correct Answer
(C) When \(\mathrm{p}+\mathrm{mf}^{\prime}(\alpha) \neq 0, \mathrm{px}+\mathrm{my}+\mathrm{n}=0\) intersects the curve \(y=f(x)\)
Step-by-step Solution
Detailed explanation
Since \(f(x)\) is a curve contains \((\alpha, \beta)\) and \(\mathrm{p} \alpha+\mathrm{m} \beta+\mathrm{n}=0\) ... (i) So, curve intersect \(\mathrm{px}+\mathrm{my}+\mathrm{n}=0\) Let equation of curve \(y=f(x)=a x^2+b x+c\)…
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