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AP EAMCET · Maths · Application of Derivatives

If \(y=\frac{2}{\sqrt{a^2-b^2}} \tan ^{-1}\left[\sqrt{\frac{a-b}{a+b}} \tan \frac{x}{2}\right]\), then \(\left.\frac{d^2 y}{d x^2}\right|_{x=\frac{\pi}{2}}=\)

  1. A \(\frac{b}{2 a^2}\)
  2. B \(\frac{b}{a^2}\)
  3. C \(\frac{2 b}{a}\)
  4. D \(\frac{b^2}{2 a}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{b}{a^2}\)

Step-by-step Solution

Detailed explanation

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